Base | Representation |
---|---|
bin | 11001110100011011110100… |
… | …111110101010111110010111 |
3 | 112220001200220020112210220010 |
4 | 121310123310332222332113 |
5 | 104340434011043110203 |
6 | 1041302110251411303 |
7 | 32630016156334002 |
oct | 3164336476527627 |
9 | 486050806483803 |
10 | 113554455441303 |
11 | 332001a0813408 |
12 | 1089b745453b33 |
13 | 4b491a6a93b36 |
14 | 20080ca3b8539 |
15 | d1dc2a66a303 |
hex | 6746f4faaf97 |
113554455441303 has 4 divisors (see below), whose sum is σ = 151405940588408. Its totient is φ = 75702970294200.
The previous prime is 113554455441293. The next prime is 113554455441311. The reversal of 113554455441303 is 303144554455311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 113554455441303 - 226 = 113554388332439 is a prime.
It is a super-2 number, since 2×1135544554413032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113554455441373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18925742573548 + ... + 18925742573553.
It is an arithmetic number, because the mean of its divisors is an integer number (37851485147102).
Almost surely, 2113554455441303 is an apocalyptic number.
113554455441303 is a deficient number, since it is larger than the sum of its proper divisors (37851485147105).
113554455441303 is an equidigital number, since it uses as much as digits as its factorization.
113554455441303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37851485147104.
The product of its (nonzero) digits is 4320000, while the sum is 48.
The spelling of 113554455441303 in words is "one hundred thirteen trillion, five hundred fifty-four billion, four hundred fifty-five million, four hundred forty-one thousand, three hundred three".
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