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113554455441303 = 337851485147101
BaseRepresentation
bin11001110100011011110100…
…111110101010111110010111
3112220001200220020112210220010
4121310123310332222332113
5104340434011043110203
61041302110251411303
732630016156334002
oct3164336476527627
9486050806483803
10113554455441303
11332001a0813408
121089b745453b33
134b491a6a93b36
1420080ca3b8539
15d1dc2a66a303
hex6746f4faaf97

113554455441303 has 4 divisors (see below), whose sum is σ = 151405940588408. Its totient is φ = 75702970294200.

The previous prime is 113554455441293. The next prime is 113554455441311. The reversal of 113554455441303 is 303144554455311.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 113554455441303 - 226 = 113554388332439 is a prime.

It is a super-2 number, since 2×1135544554413032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113554455441373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18925742573548 + ... + 18925742573553.

It is an arithmetic number, because the mean of its divisors is an integer number (37851485147102).

Almost surely, 2113554455441303 is an apocalyptic number.

113554455441303 is a deficient number, since it is larger than the sum of its proper divisors (37851485147105).

113554455441303 is an equidigital number, since it uses as much as digits as its factorization.

113554455441303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37851485147104.

The product of its (nonzero) digits is 4320000, while the sum is 48.

The spelling of 113554455441303 in words is "one hundred thirteen trillion, five hundred fifty-four billion, four hundred fifty-five million, four hundred forty-one thousand, three hundred three".

Divisors: 1 3 37851485147101 113554455441303