Search a number
-
+
113555010242309 is a prime number
BaseRepresentation
bin11001110100011100010110…
…000011000100011100000101
3112220001202022220111121210112
4121310130112003010130011
5104340441130110223214
61041302241311002405
732630036004142436
oct3164342603043405
9486052286447715
10113555010242309
11332004559aa639
121089b87b209405
134b492649c565c
14200813dd5748d
15d1dc5e20aa3e
hex6747160c4705

113555010242309 has 2 divisors, whose sum is σ = 113555010242310. Its totient is φ = 113555010242308.

The previous prime is 113555010242291. The next prime is 113555010242329. The reversal of 113555010242309 is 903242010555311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93997193896225 + 19557816346084 = 9695215^2 + 4422422^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113555010242309 is a prime.

It is a super-3 number, since 3×1135550102423093 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113555010242329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777505121154 + 56777505121155.

It is an arithmetic number, because the mean of its divisors is an integer number (56777505121155).

Almost surely, 2113555010242309 is an apocalyptic number.

It is an amenable number.

113555010242309 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555010242309 is an equidigital number, since it uses as much as digits as its factorization.

113555010242309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 113555010242309 in words is "one hundred thirteen trillion, five hundred fifty-five billion, ten million, two hundred forty-two thousand, three hundred nine".