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113555269853 is a prime number
BaseRepresentation
bin110100111000001101…
…0111110100011011101
3101212002212021101202022
41221300122332203131
53330030122113403
6124055551305525
711130001603454
oct1516032764335
9355085241668
10113555269853
1144181a97a63
121a01151b2a5
13a928c4848c
1456d344bb9b
152e492c0d38
hex1a706be8dd

113555269853 has 2 divisors, whose sum is σ = 113555269854. Its totient is φ = 113555269852.

The previous prime is 113555269819. The next prime is 113555269879. The reversal of 113555269853 is 358962555311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57119566009 + 56435703844 = 238997^2 + 237562^2 .

It is a cyclic number.

It is not a de Polignac number, because 113555269853 - 234 = 96375400669 is a prime.

It is a super-2 number, since 2×1135552698532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113555269795 and 113555269804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113555269453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777634926 + 56777634927.

It is an arithmetic number, because the mean of its divisors is an integer number (56777634927).

Almost surely, 2113555269853 is an apocalyptic number.

It is an amenable number.

113555269853 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555269853 is an equidigital number, since it uses as much as digits as its factorization.

113555269853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4860000, while the sum is 53.

The spelling of 113555269853 in words is "one hundred thirteen billion, five hundred fifty-five million, two hundred sixty-nine thousand, eight hundred fifty-three".