113555500141261 has 2 divisors, whose sum is σ = 113555500141262. Its totient is φ = 113555500141260.

The previous prime is 113555500141177. The next prime is 113555500141273. The reversal of 113555500141261 is 162141005555311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72995236875625 + 40560263265636 = 8543725^2 + 6368694^2 .

It is an emirp because it is prime and its reverse (162141005555311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113555500141261 - 2¹⁹ = 113555499616973 is a prime.

It is a super-2 number, since 2×113555500141261² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113555500141961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777750070630 + 56777750070631.

It is an arithmetic number, because the mean of its divisors is an integer number (56777750070631).

Almost surely, 2^{113555500141261} is an apocalyptic number.

It is an amenable number.

113555500141261 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555500141261 is an equidigital number, since it uses as much as digits as its factorization.

113555500141261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90000, while the sum is 40.

Adding to 113555500141261 its reverse (162141005555311), we get a palindrome (275696505696572).

The spelling of 113555500141261 in words is "one hundred thirteen trillion, five hundred fifty-five billion, five hundred million, one hundred forty-one thousand, two hundred sixty-one".