Base | Representation |
---|---|
bin | 11001110100011100110011… |
… | …001111111010111100001110 |
3 | 112220001210121001100112112220 |
4 | 121310130303033322330032 |
5 | 104340443131014304132 |
6 | 1041302402051240210 |
7 | 32630054103245352 |
oct | 3164346317727416 |
9 | 486053531315486 |
10 | 113555500150542 |
11 | 332006874a397a |
12 | 1089b9972a9066 |
13 | 4b49312356198 |
14 | 2008189043462 |
15 | d1dc8c22da2c |
hex | 6747333faf0e |
113555500150542 has 32 divisors (see below), whose sum is σ = 231444495479808. Its totient is φ = 37129882841376.
The previous prime is 113555500150459. The next prime is 113555500150597. The reversal of 113555500150542 is 245051005555311.
It is a super-3 number, since 3×1135555001505423 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 113555500150494 and 113555500150503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35808378 + ... + 38850365.
It is an arithmetic number, because the mean of its divisors is an integer number (7232640483744).
Almost surely, 2113555500150542 is an apocalyptic number.
113555500150542 is an abundant number, since it is smaller than the sum of its proper divisors (117888995329266).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113555500150542 is a wasteful number, since it uses less digits than its factorization.
113555500150542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74663584.
The product of its (nonzero) digits is 375000, while the sum is 42.
The spelling of 113555500150542 in words is "one hundred thirteen trillion, five hundred fifty-five billion, five hundred million, one hundred fifty thousand, five hundred forty-two".
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