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113555500150597 is a prime number
BaseRepresentation
bin11001110100011100110011…
…001111111010111101000101
3112220001210121001100112121221
4121310130303033322331011
5104340443131014304342
61041302402051240341
732630054103245461
oct3164346317727505
9486053531315557
10113555500150597
11332006874a3a1a
121089b9972a90b1
134b4931235620b
1420081890434a1
15d1dc8c22da67
hex6747333faf45

113555500150597 has 2 divisors, whose sum is σ = 113555500150598. Its totient is φ = 113555500150596.

The previous prime is 113555500150459. The next prime is 113555500150621. The reversal of 113555500150597 is 795051005555311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61535646825156 + 52019853325441 = 7844466^2 + 7212479^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113555500150597 is a prime.

It is a super-2 number, since 2×1135555001505972 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113555500154597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777750075298 + 56777750075299.

It is an arithmetic number, because the mean of its divisors is an integer number (56777750075299).

Almost surely, 2113555500150597 is an apocalyptic number.

It is an amenable number.

113555500150597 is a deficient number, since it is larger than the sum of its proper divisors (1).

113555500150597 is an equidigital number, since it uses as much as digits as its factorization.

113555500150597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2953125, while the sum is 52.

The spelling of 113555500150597 in words is "one hundred thirteen trillion, five hundred fifty-five billion, five hundred million, one hundred fifty thousand, five hundred ninety-seven".