Base | Representation |
---|---|
bin | 11001110100011100110011… |
… | …001111111010111101000101 |
3 | 112220001210121001100112121221 |
4 | 121310130303033322331011 |
5 | 104340443131014304342 |
6 | 1041302402051240341 |
7 | 32630054103245461 |
oct | 3164346317727505 |
9 | 486053531315557 |
10 | 113555500150597 |
11 | 332006874a3a1a |
12 | 1089b9972a90b1 |
13 | 4b4931235620b |
14 | 20081890434a1 |
15 | d1dc8c22da67 |
hex | 6747333faf45 |
113555500150597 has 2 divisors, whose sum is σ = 113555500150598. Its totient is φ = 113555500150596.
The previous prime is 113555500150459. The next prime is 113555500150621. The reversal of 113555500150597 is 795051005555311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61535646825156 + 52019853325441 = 7844466^2 + 7212479^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113555500150597 is a prime.
It is a super-2 number, since 2×1135555001505972 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113555500154597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777750075298 + 56777750075299.
It is an arithmetic number, because the mean of its divisors is an integer number (56777750075299).
Almost surely, 2113555500150597 is an apocalyptic number.
It is an amenable number.
113555500150597 is a deficient number, since it is larger than the sum of its proper divisors (1).
113555500150597 is an equidigital number, since it uses as much as digits as its factorization.
113555500150597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2953125, while the sum is 52.
The spelling of 113555500150597 in words is "one hundred thirteen trillion, five hundred fifty-five billion, five hundred million, one hundred fifty thousand, five hundred ninety-seven".
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