Base | Representation |
---|---|
bin | 11001110100011100110011… |
… | …010000100010101110111010 |
3 | 112220001210121001122211010111 |
4 | 121310130303100202232322 |
5 | 104340443131040013110 |
6 | 1041302402054534534 |
7 | 32630054104524502 |
oct | 3164346320425672 |
9 | 486053531584114 |
10 | 113555500313530 |
11 | 332006875a5380 |
12 | 1089b99736744a |
13 | 4b493123b2422 |
14 | 2008189086a02 |
15 | d1dc8c261e8a |
hex | 674733422bba |
113555500313530 has 64 divisors (see below), whose sum is σ = 223825124275200. Its totient is φ = 41136741214720.
The previous prime is 113555500313509. The next prime is 113555500313533. The reversal of 113555500313530 is 35313005555311.
It is a super-2 number, since 2×1135555003135302 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (113555500313533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 489687351 + ... + 489919189.
It is an arithmetic number, because the mean of its divisors is an integer number (3497267566800).
Almost surely, 2113555500313530 is an apocalyptic number.
113555500313530 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113555500313530 is a deficient number, since it is larger than the sum of its proper divisors (110269623961670).
113555500313530 is a wasteful number, since it uses less digits than its factorization.
113555500313530 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248679.
The product of its (nonzero) digits is 253125, while the sum is 40.
Adding to 113555500313530 its reverse (35313005555311), we get a palindrome (148868505868841).
The spelling of 113555500313530 in words is "one hundred thirteen trillion, five hundred fifty-five billion, five hundred million, three hundred thirteen thousand, five hundred thirty".
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