Base | Representation |
---|---|
bin | 10000100001100100110… |
… | …011100110110011000111 |
3 | 11000120002022101211201221 |
4 | 100201210303212303013 |
5 | 122101113012203012 |
6 | 2225400435501211 |
7 | 145020204655531 |
oct | 20414463466307 |
9 | 4016068354657 |
10 | 1135562616007 |
11 | 3a8653546836 |
12 | 1640b5757807 |
13 | 83110738921 |
14 | 3cd665c8851 |
15 | 1e812b17507 |
hex | 10864ce6cc7 |
1135562616007 has 2 divisors, whose sum is σ = 1135562616008. Its totient is φ = 1135562616006.
The previous prime is 1135562615977. The next prime is 1135562616017. The reversal of 1135562616007 is 7006162655311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1135562616007 - 211 = 1135562613959 is a prime.
It is a super-2 number, since 2×11355626160072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135562616017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567781308003 + 567781308004.
It is an arithmetic number, because the mean of its divisors is an integer number (567781308004).
Almost surely, 21135562616007 is an apocalyptic number.
1135562616007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135562616007 is an equidigital number, since it uses as much as digits as its factorization.
1135562616007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 1135562616007 in words is "one trillion, one hundred thirty-five billion, five hundred sixty-two million, six hundred sixteen thousand, seven".
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