Base | Representation |
---|---|
bin | 10000100001101111011… |
… | …001100011111011110011 |
3 | 11000120112200211001100112 |
4 | 100201233121203323303 |
5 | 122101444011303112 |
6 | 2225430225011535 |
7 | 145024463405300 |
oct | 20415731437363 |
9 | 4016480731315 |
10 | 1135740337907 |
11 | 3a87348a293a |
12 | 164145183bab |
13 | 8313b4c2906 |
14 | 3cd8204c0a7 |
15 | 1e823520a22 |
hex | 1086f663ef3 |
1135740337907 has 54 divisors (see below), whose sum is σ = 1421810059068. Its totient is φ = 904267771008.
The previous prime is 1135740337889. The next prime is 1135740337937. The reversal of 1135740337907 is 7097330475311.
It is not a de Polignac number, because 1135740337907 - 214 = 1135740321523 is a prime.
It is a super-2 number, since 2×11357403379072 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1135740337937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 1155381338 + ... + 1155382320.
Almost surely, 21135740337907 is an apocalyptic number.
1135740337907 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1135740337907 is a deficient number, since it is larger than the sum of its proper divisors (286069721161).
1135740337907 is an frugal number, since it uses more digits than its factorization.
1135740337907 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2097 (or 1090 counting only the distinct ones).
The product of its (nonzero) digits is 1666980, while the sum is 50.
The spelling of 1135740337907 in words is "one trillion, one hundred thirty-five billion, seven hundred forty million, three hundred thirty-seven thousand, nine hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •