Base | Representation |
---|---|
bin | 110100111010101000… |
… | …1000000001011001101 |
3 | 101212022112012101222201 |
4 | 1221311101000023031 |
5 | 3330211423304013 |
6 | 124112013241501 |
7 | 11132006443123 |
oct | 1516521001315 |
9 | 355275171881 |
10 | 113636541133 |
11 | 44213957305 |
12 | 1a034793291 |
13 | a93ca323ab |
14 | 5700165913 |
15 | 2e514c63dd |
hex | 1a754402cd |
113636541133 has 2 divisors, whose sum is σ = 113636541134. Its totient is φ = 113636541132.
The previous prime is 113636541127. The next prime is 113636541167. The reversal of 113636541133 is 331145636311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60864343849 + 52772197284 = 246707^2 + 229722^2 .
It is a cyclic number.
It is not a de Polignac number, because 113636541133 - 229 = 113099670221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113636541092 and 113636541101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113636541233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56818270566 + 56818270567.
It is an arithmetic number, because the mean of its divisors is an integer number (56818270567).
Almost surely, 2113636541133 is an apocalyptic number.
It is an amenable number.
113636541133 is a deficient number, since it is larger than the sum of its proper divisors (1).
113636541133 is an equidigital number, since it uses as much as digits as its factorization.
113636541133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 37.
The spelling of 113636541133 in words is "one hundred thirteen billion, six hundred thirty-six million, five hundred forty-one thousand, one hundred thirty-three".
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