Base | Representation |
---|---|
bin | 10101001011010010… |
… | …01111100010110111 |
3 | 1002100022202100222110 |
4 | 22211221033202313 |
5 | 141240430034212 |
6 | 5120044502103 |
7 | 551506536063 |
oct | 124551174267 |
9 | 32308670873 |
10 | 11368986807 |
11 | 4904551072 |
12 | 225354a933 |
13 | 10c24caa39 |
14 | 79bcc0aa3 |
15 | 468178a3c |
hex | 2a5a4f8b7 |
11368986807 has 8 divisors (see below), whose sum is σ = 15160978800. Its totient is φ = 7578159680.
The previous prime is 11368986803. The next prime is 11368986809. The reversal of 11368986807 is 70868986311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11368986807 - 22 = 11368986803 is a prime.
It is a super-2 number, since 2×113689868072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11368986803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268182 + ... + 307667.
It is an arithmetic number, because the mean of its divisors is an integer number (1895122350).
Almost surely, 211368986807 is an apocalyptic number.
11368986807 is a deficient number, since it is larger than the sum of its proper divisors (3791991993).
11368986807 is an equidigital number, since it uses as much as digits as its factorization.
11368986807 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 582433.
The product of its (nonzero) digits is 3483648, while the sum is 57.
The spelling of 11368986807 in words is "eleven billion, three hundred sixty-eight million, nine hundred eighty-six thousand, eight hundred seven".
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