Base | Representation |
---|---|
bin | 10000100010111011000… |
… | …001100011011011001111 |
3 | 11000200211010020111021121 |
4 | 100202323001203123033 |
5 | 122112043313102113 |
6 | 2230200151141411 |
7 | 145101100665355 |
oct | 20427301433317 |
9 | 4020733214247 |
10 | 1137009112783 |
11 | 3a9226003215 |
12 | 16443a074867 |
13 | 832b131708b |
14 | 3d0627617d5 |
15 | 1e899ae3e8d |
hex | 108bb0636cf |
1137009112783 has 2 divisors, whose sum is σ = 1137009112784. Its totient is φ = 1137009112782.
The previous prime is 1137009112753. The next prime is 1137009112787. The reversal of 1137009112783 is 3872119007311.
It is a strong prime.
It is an emirp because it is prime and its reverse (3872119007311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1137009112783 - 29 = 1137009112271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1137009112787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 568504556391 + 568504556392.
It is an arithmetic number, because the mean of its divisors is an integer number (568504556392).
Almost surely, 21137009112783 is an apocalyptic number.
1137009112783 is a deficient number, since it is larger than the sum of its proper divisors (1).
1137009112783 is an equidigital number, since it uses as much as digits as its factorization.
1137009112783 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 43.
The spelling of 1137009112783 in words is "one trillion, one hundred thirty-seven billion, nine million, one hundred twelve thousand, seven hundred eighty-three".
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