Base | Representation |
---|---|
bin | 10101001011110011… |
… | …00000100111101111 |
3 | 1002100121210000102120 |
4 | 22211321200213233 |
5 | 141243023013210 |
6 | 5120320124023 |
7 | 551561016225 |
oct | 124571404757 |
9 | 32317700376 |
10 | 11373251055 |
11 | 49069a3941 |
12 | 2254a66613 |
13 | 10c336196a |
14 | 79c6b0b15 |
15 | 46871c270 |
hex | 2a5e609ef |
11373251055 has 16 divisors (see below), whose sum is σ = 18584377344. Its totient is φ = 5936675360.
The previous prime is 11373251027. The next prime is 11373251063. The reversal of 11373251055 is 55015237311.
It is not a de Polignac number, because 11373251055 - 25 = 11373251023 is a prime.
It is a super-2 number, since 2×113732510552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8065431 + ... + 8066840.
It is an arithmetic number, because the mean of its divisors is an integer number (1161523584).
Almost surely, 211373251055 is an apocalyptic number.
11373251055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11373251055 is a deficient number, since it is larger than the sum of its proper divisors (7211126289).
11373251055 is a wasteful number, since it uses less digits than its factorization.
11373251055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16132326.
The product of its (nonzero) digits is 15750, while the sum is 33.
Adding to 11373251055 its reverse (55015237311), we get a palindrome (66388488366).
The spelling of 11373251055 in words is "eleven billion, three hundred seventy-three million, two hundred fifty-one thousand, fifty-five".
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