Base | Representation |
---|---|
bin | 10101001100000100… |
… | …10101000101101101 |
3 | 1002100210010110222111 |
4 | 22212002111011231 |
5 | 141244121004432 |
6 | 5120441444021 |
7 | 551616456022 |
oct | 124602250555 |
9 | 32323113874 |
10 | 11375563117 |
11 | 4908232a36 |
12 | 22557a0611 |
13 | 10c3991149 |
14 | 79cb13549 |
15 | 468a27347 |
hex | 2a609516d |
11375563117 has 2 divisors, whose sum is σ = 11375563118. Its totient is φ = 11375563116.
The previous prime is 11375563099. The next prime is 11375563163. The reversal of 11375563117 is 71136557311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6079944676 + 5295618441 = 77974^2 + 72771^2 .
It is a cyclic number.
It is not a de Polignac number, because 11375563117 - 215 = 11375530349 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11375563117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11375563417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5687781558 + 5687781559.
It is an arithmetic number, because the mean of its divisors is an integer number (5687781559).
Almost surely, 211375563117 is an apocalyptic number.
It is an amenable number.
11375563117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11375563117 is an equidigital number, since it uses as much as digits as its factorization.
11375563117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 66150, while the sum is 40.
The spelling of 11375563117 in words is "eleven billion, three hundred seventy-five million, five hundred sixty-three thousand, one hundred seventeen".
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