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113775750419 is a prime number
BaseRepresentation
bin110100111110110010…
…0000010110100010011
3101212200020010222020012
41221331210002310103
53331003043003134
6124133505105135
711135316631112
oct1517544026423
9355606128205
10113775750419
1144285499301
121a0733281ab
13a962823856
145714841c79
152e5d8236ce
hex1a7d902d13

113775750419 has 2 divisors, whose sum is σ = 113775750420. Its totient is φ = 113775750418.

The previous prime is 113775750371. The next prime is 113775750421. The reversal of 113775750419 is 914057577311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113775750419 is a prime.

It is a super-2 number, since 2×1137757504192 (a number of 23 digits) contains 22 as substring.

Together with 113775750421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113775750919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56887875209 + 56887875210.

It is an arithmetic number, because the mean of its divisors is an integer number (56887875210).

Almost surely, 2113775750419 is an apocalyptic number.

113775750419 is a deficient number, since it is larger than the sum of its proper divisors (1).

113775750419 is an equidigital number, since it uses as much as digits as its factorization.

113775750419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 926100, while the sum is 50.

The spelling of 113775750419 in words is "one hundred thirteen billion, seven hundred seventy-five million, seven hundred fifty thousand, four hundred nineteen".