113900131 has 2 divisors, whose sum is σ = 113900132. Its totient is φ = 113900130.

The previous prime is 113900113. The next prime is 113900147. The reversal of 113900131 is 131009311.

It is a happy number.

Together with previous prime (113900113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113900131 - 2²¹ = 111802979 is a prime.

It is a super-2 number, since 2×113900131² = 25946479683634322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113900099 and 113900108.

It is not a weakly prime, because it can be changed into another prime (113900161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56950065 + 56950066.

It is an arithmetic number, because the mean of its divisors is an integer number (56950066).

Almost surely, 2^113900131 is an apocalyptic number.

113900131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113900131 is an equidigital number, since it uses as much as digits as its factorization.

113900131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 19.

The square root of 113900131 is about 10672.4004328923. The cubic root of 113900131 is about 484.7391249464.

Adding to 113900131 its reverse (131009311), we get a palindrome (244909442).

The spelling of 113900131 in words is "one hundred thirteen million, nine hundred thousand, one hundred thirty-one".