Base | Representation |
---|---|
bin | 10101001110111001… |
… | …11000010101100101 |
3 | 1002102102210110111002 |
4 | 22213130320111211 |
5 | 141321210103303 |
6 | 5123050323045 |
7 | 552325312052 |
oct | 124734702545 |
9 | 32372713432 |
10 | 11399300453 |
11 | 491a676172 |
12 | 2261729485 |
13 | 10c88826c8 |
14 | 7a1d32029 |
15 | 46ab65788 |
hex | 2a7738565 |
11399300453 has 4 divisors (see below), whose sum is σ = 11424689100. Its totient is φ = 11373911808.
The previous prime is 11399300447. The next prime is 11399300489. The reversal of 11399300453 is 35400399311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9284864164 + 2114436289 = 96358^2 + 45983^2 .
It is a cyclic number.
It is not a de Polignac number, because 11399300453 - 212 = 11399296357 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11399300443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12693650 + ... + 12694547.
It is an arithmetic number, because the mean of its divisors is an integer number (2856172275).
Almost surely, 211399300453 is an apocalyptic number.
It is an amenable number.
11399300453 is a deficient number, since it is larger than the sum of its proper divisors (25388647).
11399300453 is an equidigital number, since it uses as much as digits as its factorization.
11399300453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25388646.
The product of its (nonzero) digits is 43740, while the sum is 38.
Adding to 11399300453 its reverse (35400399311), we get a palindrome (46799699764).
The spelling of 11399300453 in words is "eleven billion, three hundred ninety-nine million, three hundred thousand, four hundred fifty-three".
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