Base | Representation |
---|---|
bin | 1010010111100010001101… |
… | …0001100100101111111111 |
3 | 1111100202221020002202000012 |
4 | 2211320203101210233333 |
5 | 2443232020330404434 |
6 | 40124454514053435 |
7 | 2254403424603266 |
oct | 245704321445777 |
9 | 44322836082005 |
10 | 11399435013119 |
11 | 36a55229782aa |
12 | 134135387a27b |
13 | 648c679a551a |
14 | 2b5a426a75dd |
15 | 14b7d369e3ce |
hex | a5e23464bff |
11399435013119 has 2 divisors, whose sum is σ = 11399435013120. Its totient is φ = 11399435013118.
The previous prime is 11399435013103. The next prime is 11399435013139. The reversal of 11399435013119 is 91131053499311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11399435013119 - 24 = 11399435013103 is a prime.
It is a super-2 number, since 2×113994350131192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11399435013139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5699717506559 + 5699717506560.
It is an arithmetic number, because the mean of its divisors is an integer number (5699717506560).
Almost surely, 211399435013119 is an apocalyptic number.
11399435013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
11399435013119 is an equidigital number, since it uses as much as digits as its factorization.
11399435013119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 393660, while the sum is 50.
The spelling of 11399435013119 in words is "eleven trillion, three hundred ninety-nine billion, four hundred thirty-five million, thirteen thousand, one hundred nineteen".
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