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1139960935152 = 243513316311153
BaseRepresentation
bin10000100101101010111…
…101110111001011110000
311000222102211121121100000
4100211222331313023300
5122134114444411102
62231405115030000
7145234203033444
oct20455275671360
94028384547300
101139960935152
113aa500258036
12164b2273b300
1383661a30830
143d2627c6824
151e9bdd1d01c
hex1096af772f0

1139960935152 has 480 divisors, whose sum is σ = 3686922244096. Its totient is φ = 338610585600.

The previous prime is 1139960935129. The next prime is 1139960935177. The reversal of 1139960935152 is 2515390699311.

1139960935152 is a `hidden beast` number, since 1 + 1 + 39 + 9 + 6 + 0 + 93 + 515 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 988690608 + ... + 988691760.

Almost surely, 21139960935152 is an apocalyptic number.

1139960935152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1139960935152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1843461122048).

1139960935152 is an abundant number, since it is smaller than the sum of its proper divisors (2546961308944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1139960935152 is a wasteful number, since it uses less digits than its factorization.

1139960935152 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1851 (or 1833 counting only the distinct ones).

The product of its (nonzero) digits is 1968300, while the sum is 54.

The spelling of 1139960935152 in words is "one trillion, one hundred thirty-nine billion, nine hundred sixty million, nine hundred thirty-five thousand, one hundred fifty-two".