Base | Representation |
---|---|
bin | 10000100101101011010… |
… | …101001000001100100011 |
3 | 11000222110021002110120201 |
4 | 100211223111020030203 |
5 | 122134123030043042 |
6 | 2231405453450031 |
7 | 145234305624664 |
oct | 20455325101443 |
9 | 4028407073521 |
10 | 1139967034147 |
11 | 3aa503743327 |
12 | 164b247a0917 |
13 | 836630878c6 |
14 | 3d26353336b |
15 | 1e9be6251b7 |
hex | 1096b548323 |
1139967034147 has 2 divisors, whose sum is σ = 1139967034148. Its totient is φ = 1139967034146.
The previous prime is 1139967034099. The next prime is 1139967034163. The reversal of 1139967034147 is 7414307699311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1139967034147 - 239 = 590211220259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1139967032147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569983517073 + 569983517074.
It is an arithmetic number, because the mean of its divisors is an integer number (569983517074).
Almost surely, 21139967034147 is an apocalyptic number.
1139967034147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1139967034147 is an equidigital number, since it uses as much as digits as its factorization.
1139967034147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3429216, while the sum is 55.
The spelling of 1139967034147 in words is "one trillion, one hundred thirty-nine billion, nine hundred sixty-seven million, thirty-four thousand, one hundred forty-seven".
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