Base | Representation |
---|---|
bin | 11001111010111010110001… |
… | …110011110111001100101111 |
3 | 112221122021221100220021100011 |
4 | 121322322301303313030233 |
5 | 104420234002303224403 |
6 | 1042242513535514051 |
7 | 33004141254252205 |
oct | 3172726163671457 |
9 | 487567840807304 |
10 | 114000005133103 |
11 | 33362148a183a1 |
12 | 10951b6b088927 |
13 | 4b7c20117641b |
14 | 20218b5c19075 |
15 | d2a605d83a6d |
hex | 67aeb1cf732f |
114000005133103 has 2 divisors, whose sum is σ = 114000005133104. Its totient is φ = 114000005133102.
The previous prime is 114000005133089. The next prime is 114000005133121. The reversal of 114000005133103 is 301331500000411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114000005133103 - 25 = 114000005133071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114000005133143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000002566551 + 57000002566552.
It is an arithmetic number, because the mean of its divisors is an integer number (57000002566552).
Almost surely, 2114000005133103 is an apocalyptic number.
114000005133103 is a deficient number, since it is larger than the sum of its proper divisors (1).
114000005133103 is an equidigital number, since it uses as much as digits as its factorization.
114000005133103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 114000005133103 its reverse (301331500000411), we get a palindrome (415331505133514).
The spelling of 114000005133103 in words is "one hundred fourteen trillion, five million, one hundred thirty-three thousand, one hundred three".
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