Base | Representation |
---|---|
bin | 110101000101100000… |
… | …0001110100101010011 |
3 | 101220020221110011010221 |
4 | 1222023000032211103 |
5 | 3331433304224301 |
6 | 124212122133511 |
7 | 11144025400225 |
oct | 1521300164523 |
9 | 356227404127 |
10 | 114001242451 |
11 | 44390802858 |
12 | 1a116951297 |
13 | a99a464ca5 |
14 | 573677c415 |
15 | 2e73515da1 |
hex | 1a8b00e953 |
114001242451 has 2 divisors, whose sum is σ = 114001242452. Its totient is φ = 114001242450.
The previous prime is 114001242449. The next prime is 114001242479. The reversal of 114001242451 is 154242100411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114001242451 - 21 = 114001242449 is a prime.
Together with 114001242449, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (114001243451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000621225 + 57000621226.
It is an arithmetic number, because the mean of its divisors is an integer number (57000621226).
Almost surely, 2114001242451 is an apocalyptic number.
114001242451 is a deficient number, since it is larger than the sum of its proper divisors (1).
114001242451 is an equidigital number, since it uses as much as digits as its factorization.
114001242451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 114001242451 its reverse (154242100411), we get a palindrome (268243342862).
The spelling of 114001242451 in words is "one hundred fourteen billion, one million, two hundred forty-two thousand, four hundred fifty-one".
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