Base | Representation |
---|---|
bin | 10101001111000000… |
… | …10111101111111111 |
3 | 1002102111111221202121 |
4 | 22213200113233333 |
5 | 141321423344201 |
6 | 5123122103411 |
7 | 552336143014 |
oct | 124740275777 |
9 | 32374457677 |
10 | 11400215551 |
11 | 492014074a |
12 | 2261aaab67 |
13 | 10c8b1309a |
14 | 7a20cd70b |
15 | 46ac969a1 |
hex | 2a7817bff |
11400215551 has 2 divisors, whose sum is σ = 11400215552. Its totient is φ = 11400215550.
The previous prime is 11400215537. The next prime is 11400215591. The reversal of 11400215551 is 15551200411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11400215551 - 213 = 11400207359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11400215591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700107775 + 5700107776.
It is an arithmetic number, because the mean of its divisors is an integer number (5700107776).
Almost surely, 211400215551 is an apocalyptic number.
11400215551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11400215551 is an equidigital number, since it uses as much as digits as its factorization.
11400215551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1000, while the sum is 25.
Adding to 11400215551 its reverse (15551200411), we get a palindrome (26951415962).
The spelling of 11400215551 in words is "eleven billion, four hundred million, two hundred fifteen thousand, five hundred fifty-one".
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