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114002433123 = 338000811041
BaseRepresentation
bin110101000101100010…
…0110001010001100011
3101220021000200122102220
41222023010301101203
53331434110324443
6124212203442123
711144041456455
oct1521304612143
9356230618386
10114002433123
1144391446387
121a117226343
13a99a790c27
1457369ac2d5
152e7369da83
hex1a8b131463

114002433123 has 4 divisors (see below), whose sum is σ = 152003244168. Its totient is φ = 76001622080.

The previous prime is 114002433119. The next prime is 114002433131. The reversal of 114002433123 is 321334200411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114002433123 - 22 = 114002433119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114002433093 and 114002433102.

It is not an unprimeable number, because it can be changed into a prime (114002433163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19000405518 + ... + 19000405523.

It is an arithmetic number, because the mean of its divisors is an integer number (38000811042).

Almost surely, 2114002433123 is an apocalyptic number.

114002433123 is a deficient number, since it is larger than the sum of its proper divisors (38000811045).

114002433123 is an equidigital number, since it uses as much as digits as its factorization.

114002433123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38000811044.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 114002433123 its reverse (321334200411), we get a palindrome (435336633534).

The spelling of 114002433123 in words is "one hundred fourteen billion, two million, four hundred thirty-three thousand, one hundred twenty-three".

Divisors: 1 3 38000811041 114002433123