Base | Representation |
---|---|
bin | 10000100101101111010… |
… | …101111000110110111011 |
3 | 11000222121221202002001102 |
4 | 100211233111320312323 |
5 | 122134242242423311 |
6 | 2231420300242015 |
7 | 145236054010523 |
oct | 20455725706673 |
9 | 4028557662042 |
10 | 1140034342331 |
11 | 3aa538735a25 |
12 | 164b4324030b |
13 | 83673cc3131 |
14 | 3d26c454683 |
15 | 1e9c54bd43b |
hex | 1096f578dbb |
1140034342331 has 2 divisors, whose sum is σ = 1140034342332. Its totient is φ = 1140034342330.
The previous prime is 1140034342303. The next prime is 1140034342379. The reversal of 1140034342331 is 1332434300411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140034342331 is a prime.
It is a super-2 number, since 2×11400343423312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1140034342294 and 1140034342303.
It is not a weakly prime, because it can be changed into another prime (1140034342231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570017171165 + 570017171166.
It is an arithmetic number, because the mean of its divisors is an integer number (570017171166).
Almost surely, 21140034342331 is an apocalyptic number.
1140034342331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140034342331 is an equidigital number, since it uses as much as digits as its factorization.
1140034342331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1140034342331 its reverse (1332434300411), we get a palindrome (2472468642742).
The spelling of 1140034342331 in words is "one trillion, one hundred forty billion, thirty-four million, three hundred forty-two thousand, three hundred thirty-one".
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