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114010514135555 = 522802102827111
BaseRepresentation
bin11001111011000100100100…
…001100100001101000000011
3112221200022001202102220120012
4121323010210030201220003
5104420422013104314210
61042251412424135135
733004662552304262
oct3173044414415003
9487608052386505
10114010514135555
1133366650a88494
12109540026074ab
134b801b744b47b
1420221d17d85d9
15d2aa1d787305
hex67b124321a03

114010514135555 has 4 divisors (see below), whose sum is σ = 136812616962672. Its totient is φ = 91208411308440.

The previous prime is 114010514135537. The next prime is 114010514135561. The reversal of 114010514135555 is 555531415010411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 114010514135555 - 26 = 114010514135491 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11401051413551 + ... + 11401051413560.

It is an arithmetic number, because the mean of its divisors is an integer number (34203154240668).

Almost surely, 2114010514135555 is an apocalyptic number.

114010514135555 is a deficient number, since it is larger than the sum of its proper divisors (22802102827117).

114010514135555 is an equidigital number, since it uses as much as digits as its factorization.

114010514135555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22802102827116.

The product of its (nonzero) digits is 150000, while the sum is 41.

Adding to 114010514135555 its reverse (555531415010411), we get a palindrome (669541929145966).

The spelling of 114010514135555 in words is "one hundred fourteen trillion, ten billion, five hundred fourteen million, one hundred thirty-five thousand, five hundred fifty-five".

Divisors: 1 5 22802102827111 114010514135555