Base | Representation |
---|---|
bin | 11001111011000101000010… |
… | …100111000111011000010111 |
3 | 112221200100101022122011112211 |
4 | 121323011002213013120113 |
5 | 104420424034223004143 |
6 | 1042251535213254251 |
7 | 33005011316544142 |
oct | 3173050247073027 |
9 | 487610338564484 |
10 | 114011024422423 |
11 | 33366893030577 |
12 | 10954125494387 |
13 | 4b8026909586b |
14 | 202223d4ab059 |
15 | d2aa4d48349d |
hex | 67b1429c7617 |
114011024422423 has 2 divisors, whose sum is σ = 114011024422424. Its totient is φ = 114011024422422.
The previous prime is 114011024422367. The next prime is 114011024422469. The reversal of 114011024422423 is 324224420110411.
It is a strong prime.
It is an emirp because it is prime and its reverse (324224420110411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114011024422423 - 245 = 78826652333591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114011024422223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005512211211 + 57005512211212.
It is an arithmetic number, because the mean of its divisors is an integer number (57005512211212).
Almost surely, 2114011024422423 is an apocalyptic number.
114011024422423 is a deficient number, since it is larger than the sum of its proper divisors (1).
114011024422423 is an equidigital number, since it uses as much as digits as its factorization.
114011024422423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 114011024422423 its reverse (324224420110411), we get a palindrome (438235444532834).
The spelling of 114011024422423 in words is "one hundred fourteen trillion, eleven billion, twenty-four million, four hundred twenty-two thousand, four hundred twenty-three".
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