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114011321400421 is a prime number
BaseRepresentation
bin11001111011000101010100…
…010011111111110001100101
3112221200101011000110012202221
4121323011110103333301211
5104420430141234303141
61042252024502432341
733005021554036204
oct3173052423776145
9487611130405687
10114011321400421
1133366a25730535
12109541a8a326b1
134b802b5775ca3
14202226aad523b
15d2aa69596bd1
hex67b1544ffc65

114011321400421 has 2 divisors, whose sum is σ = 114011321400422. Its totient is φ = 114011321400420.

The previous prime is 114011321400359. The next prime is 114011321400443. The reversal of 114011321400421 is 124004123110411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113838336945025 + 172984455396 = 10669505^2 + 415914^2 .

It is a cyclic number.

It is not a de Polignac number, because 114011321400421 - 215 = 114011321367653 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114011321410421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005660700210 + 57005660700211.

It is an arithmetic number, because the mean of its divisors is an integer number (57005660700211).

Almost surely, 2114011321400421 is an apocalyptic number.

It is an amenable number.

114011321400421 is a deficient number, since it is larger than the sum of its proper divisors (1).

114011321400421 is an equidigital number, since it uses as much as digits as its factorization.

114011321400421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 114011321400421 its reverse (124004123110411), we get a palindrome (238015444510832).

The spelling of 114011321400421 in words is "one hundred fourteen trillion, eleven billion, three hundred twenty-one million, four hundred thousand, four hundred twenty-one".