1140113431 has 2 divisors, whose sum is σ = 1140113432. Its totient is φ = 1140113430.

The previous prime is 1140113419. The next prime is 1140113437. The reversal of 1140113431 is 1343110411.

It is a strong prime.

It is an emirp because it is prime and its reverse (1343110411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140113431 - 2²³ = 1131724823 is a prime.

It is a super-2 number, since 2×1140113431² = 2599717271093183522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140113399 and 1140113408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140113437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570056715 + 570056716.

It is an arithmetic number, because the mean of its divisors is an integer number (570056716).

Almost surely, 2^1140113431 is an apocalyptic number.

1140113431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140113431 is an equidigital number, since it uses as much as digits as its factorization.

1140113431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1140113431 is about 33765.5657586246. The cubic root of 1140113431 is about 1044.6785733356.

Adding to 1140113431 its reverse (1343110411), we get a palindrome (2483223842).

The spelling of 1140113431 in words is "one billion, one hundred forty million, one hundred thirteen thousand, four hundred thirty-one".