Base | Representation |
---|---|
bin | 110101000101110011… |
… | …1001000010001001011 |
3 | 101220021122122020211110 |
4 | 1222023213020101023 |
5 | 3331443412041303 |
6 | 124213124501403 |
7 | 11144211152253 |
oct | 1521347102113 |
9 | 356248566743 |
10 | 114011440203 |
11 | 44396538551 |
12 | 1a11a24a863 |
13 | a99c5c586b |
14 | 5737c74963 |
15 | 2e7437c703 |
hex | 1a8b9c844b |
114011440203 has 4 divisors (see below), whose sum is σ = 152015253608. Its totient is φ = 76007626800.
The previous prime is 114011440189. The next prime is 114011440211. The reversal of 114011440203 is 302044110411.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 114011440203 - 25 = 114011440171 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 114011440203.
It is not an unprimeable number, because it can be changed into a prime (114011440003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19001906698 + ... + 19001906703.
It is an arithmetic number, because the mean of its divisors is an integer number (38003813402).
Almost surely, 2114011440203 is an apocalyptic number.
114011440203 is a deficient number, since it is larger than the sum of its proper divisors (38003813405).
114011440203 is an equidigital number, since it uses as much as digits as its factorization.
114011440203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38003813404.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 114011440203 its reverse (302044110411), we get a palindrome (416055550614).
The spelling of 114011440203 in words is "one hundred fourteen billion, eleven million, four hundred forty thousand, two hundred three".
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