Base | Representation |
---|---|
bin | 11001111011000101011111… |
… | …000010101111001101011101 |
3 | 112221200101121120012102202111 |
4 | 121323011133002233031131 |
5 | 104420431023331104001 |
6 | 1042252054413154021 |
7 | 33005026201160521 |
oct | 3173053702571535 |
9 | 487611546172674 |
10 | 114011501425501 |
11 | 3336700830aa99 |
12 | 1095423918b911 |
13 | 4b80313b583c4 |
14 | 2022286997d81 |
15 | d2aa7a2a7851 |
hex | 67b15f0af35d |
114011501425501 has 2 divisors, whose sum is σ = 114011501425502. Its totient is φ = 114011501425500.
The previous prime is 114011501425489. The next prime is 114011501425561. The reversal of 114011501425501 is 105524105110411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112584195724900 + 1427305700601 = 10610570^2 + 1194699^2 .
It is a cyclic number.
It is not a de Polignac number, because 114011501425501 - 213 = 114011501417309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114011501425561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005750712750 + 57005750712751.
It is an arithmetic number, because the mean of its divisors is an integer number (57005750712751).
Almost surely, 2114011501425501 is an apocalyptic number.
It is an amenable number.
114011501425501 is a deficient number, since it is larger than the sum of its proper divisors (1).
114011501425501 is an equidigital number, since it uses as much as digits as its factorization.
114011501425501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 31.
Adding to 114011501425501 its reverse (105524105110411), we get a palindrome (219535606535912).
The spelling of 114011501425501 in words is "one hundred fourteen trillion, eleven billion, five hundred one million, four hundred twenty-five thousand, five hundred one".
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