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114011510003981 is a prime number
BaseRepresentation
bin11001111011000101011111…
…100011011101100100001101
3112221200101122011100021012222
4121323011133203131210031
5104420431033030111411
61042252055321105125
733005026334116622
oct3173053743354415
9487611564307188
10114011510003981
113336701213a147
12109542400281a5
134b8031586cc25
142022287b8c349
15d2aa7adee4db
hex67b15f8dd90d

114011510003981 has 2 divisors, whose sum is σ = 114011510003982. Its totient is φ = 114011510003980.

The previous prime is 114011510003971. The next prime is 114011510004019. The reversal of 114011510003981 is 189300015110411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105229231096900 + 8782278907081 = 10258130^2 + 2963491^2 .

It is an emirp because it is prime and its reverse (189300015110411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114011510003981 - 218 = 114011509741837 is a prime.

It is a super-2 number, since 2×1140115100039812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114011510003971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005755001990 + 57005755001991.

It is an arithmetic number, because the mean of its divisors is an integer number (57005755001991).

Almost surely, 2114011510003981 is an apocalyptic number.

It is an amenable number.

114011510003981 is a deficient number, since it is larger than the sum of its proper divisors (1).

114011510003981 is an equidigital number, since it uses as much as digits as its factorization.

114011510003981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 35.

The spelling of 114011510003981 in words is "one hundred fourteen trillion, eleven billion, five hundred ten million, three thousand, nine hundred eighty-one".