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11401213303 = 37930082357
BaseRepresentation
bin10101001111001000…
…01011010101110111
31002102120101122102101
422213210023111313
5141322202311203
65123155322531
7552350466634
oct124744132567
932376348371
1011401213303
114920762337
1222622b0447
1310c90a227c
147a22ad18b
1546ade241d
hex2a790b577

11401213303 has 4 divisors (see below), whose sum is σ = 11431296040. Its totient is φ = 11371130568.

The previous prime is 11401213267. The next prime is 11401213379. The reversal of 11401213303 is 30331210411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11401213303 - 221 = 11399116151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11401213393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15040800 + ... + 15041557.

It is an arithmetic number, because the mean of its divisors is an integer number (2857824010).

Almost surely, 211401213303 is an apocalyptic number.

11401213303 is a deficient number, since it is larger than the sum of its proper divisors (30082737).

11401213303 is an equidigital number, since it uses as much as digits as its factorization.

11401213303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30082736.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11401213303 its reverse (30331210411), we get a palindrome (41732423714).

The spelling of 11401213303 in words is "eleven billion, four hundred one million, two hundred thirteen thousand, three hundred three".

Divisors: 1 379 30082357 11401213303