1140121333303 has 4 divisors (see below), whose sum is σ = 1140151760280. Its totient is φ = 1140090906328.

The previous prime is 1140121333289. The next prime is 1140121333327. The reversal of 1140121333303 is 3033331210411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140121333303 - 2²⁵ = 1140087778871 is a prime.

It is a super-2 number, since 2×1140121333303² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140121333343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15157213 + ... + 15232246.

It is an arithmetic number, because the mean of its divisors is an integer number (285037940070).

Almost surely, 2^{1140121333303} is an apocalyptic number.

1140121333303 is a deficient number, since it is larger than the sum of its proper divisors (30426977).

1140121333303 is an equidigital number, since it uses as much as digits as its factorization.

1140121333303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30426976.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1140121333303 its reverse (3033331210411), we get a palindrome (4173452543714).

The spelling of 1140121333303 in words is "one trillion, one hundred forty billion, one hundred twenty-one million, three hundred thirty-three thousand, three hundred three".