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1140122014111 = 9531196350487
BaseRepresentation
bin10000100101110100100…
…100010101000110011111
311000222212001201021010101
4100211310210111012133
5122134432213422421
62231433111321531
7145241200135423
oct20456444250637
94028761637111
101140122014111
113aa583177043
12164b686802a7
138368920b422
143d279d56b83
151e9cd03a191
hex1097491519f

1140122014111 has 4 divisors (see below), whose sum is σ = 1141318365552. Its totient is φ = 1138925662672.

The previous prime is 1140122014079. The next prime is 1140122014139. The reversal of 1140122014111 is 1114102210411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140122014111 - 25 = 1140122014079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140122014151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598174291 + ... + 598176196.

It is an arithmetic number, because the mean of its divisors is an integer number (285329591388).

Almost surely, 21140122014111 is an apocalyptic number.

1140122014111 is a deficient number, since it is larger than the sum of its proper divisors (1196351441).

1140122014111 is an equidigital number, since it uses as much as digits as its factorization.

1140122014111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1196351440.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 1140122014111 its reverse (1114102210411), we get a palindrome (2254224224522).

The spelling of 1140122014111 in words is "one trillion, one hundred forty billion, one hundred twenty-two million, fourteen thousand, one hundred eleven".

Divisors: 1 953 1196350487 1140122014111