114012500311441 has 4 divisors (see below), whose sum is σ = 114202838376000. Its totient is φ = 113822162246884.

The previous prime is 114012500311439. The next prime is 114012500311471. The reversal of 114012500311441 is 144113005210411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114012500311441 - 2¹ = 114012500311439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114012500311471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95169031381 + ... + 95169032578.

It is an arithmetic number, because the mean of its divisors is an integer number (28550709594000).

Almost surely, 2^{114012500311441} is an apocalyptic number.

It is an amenable number.

114012500311441 is a deficient number, since it is larger than the sum of its proper divisors (190338064559).

114012500311441 is an equidigital number, since it uses as much as digits as its factorization.

114012500311441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190338064558.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 114012500311441 its reverse (144113005210411), we get a palindrome (258125505521852).

The spelling of 114012500311441 in words is "one hundred fourteen trillion, twelve billion, five hundred million, three hundred eleven thousand, four hundred forty-one".