114012500311471 has 2 divisors, whose sum is σ = 114012500311472. Its totient is φ = 114012500311470.

The previous prime is 114012500311439. The next prime is 114012500311499. The reversal of 114012500311471 is 174113005210411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114012500311471 - 2⁵ = 114012500311439 is a prime.

It is a super-3 number, since 3×114012500311471³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114012500318471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006250155735 + 57006250155736.

It is an arithmetic number, because the mean of its divisors is an integer number (57006250155736).

Almost surely, 2^{114012500311471} is an apocalyptic number.

114012500311471 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012500311471 is an equidigital number, since it uses as much as digits as its factorization.

114012500311471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 31.

Adding to 114012500311471 its reverse (174113005210411), we get a palindrome (288125505521882).

The spelling of 114012500311471 in words is "one hundred fourteen trillion, twelve billion, five hundred million, three hundred eleven thousand, four hundred seventy-one".