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114012502121423 is a prime number
BaseRepresentation
bin11001111011000110011010…
…101100000101101111001111
3112221200111012022012001111102
4121323012122230011233033
5104420440101020341143
61042252342001413315
733005063042020403
oct3173063254055717
9487614168161442
10114012502121423
1133367481169714
121095447833a23b
134b8044327a279
14202233d847103
15d2aad80750b8
hex67b19ab05bcf

114012502121423 has 2 divisors, whose sum is σ = 114012502121424. Its totient is φ = 114012502121422.

The previous prime is 114012502121417. The next prime is 114012502121443. The reversal of 114012502121423 is 324121205210411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114012502121423 - 24 = 114012502121407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114012502121443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006251060711 + 57006251060712.

It is an arithmetic number, because the mean of its divisors is an integer number (57006251060712).

Almost surely, 2114012502121423 is an apocalyptic number.

114012502121423 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012502121423 is an equidigital number, since it uses as much as digits as its factorization.

114012502121423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 114012502121423 its reverse (324121205210411), we get a palindrome (438133707331834).

The spelling of 114012502121423 in words is "one hundred fourteen trillion, twelve billion, five hundred two million, one hundred twenty-one thousand, four hundred twenty-three".