Base | Representation |
---|---|
bin | 11001111011000110011010… |
… | …101100000101101111001111 |
3 | 112221200111012022012001111102 |
4 | 121323012122230011233033 |
5 | 104420440101020341143 |
6 | 1042252342001413315 |
7 | 33005063042020403 |
oct | 3173063254055717 |
9 | 487614168161442 |
10 | 114012502121423 |
11 | 33367481169714 |
12 | 1095447833a23b |
13 | 4b8044327a279 |
14 | 202233d847103 |
15 | d2aad80750b8 |
hex | 67b19ab05bcf |
114012502121423 has 2 divisors, whose sum is σ = 114012502121424. Its totient is φ = 114012502121422.
The previous prime is 114012502121417. The next prime is 114012502121443. The reversal of 114012502121423 is 324121205210411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114012502121423 - 24 = 114012502121407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114012502121443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006251060711 + 57006251060712.
It is an arithmetic number, because the mean of its divisors is an integer number (57006251060712).
Almost surely, 2114012502121423 is an apocalyptic number.
114012502121423 is a deficient number, since it is larger than the sum of its proper divisors (1).
114012502121423 is an equidigital number, since it uses as much as digits as its factorization.
114012502121423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 114012502121423 its reverse (324121205210411), we get a palindrome (438133707331834).
The spelling of 114012502121423 in words is "one hundred fourteen trillion, twelve billion, five hundred two million, one hundred twenty-one thousand, four hundred twenty-three".
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