Base | Representation |
---|---|
bin | 11001111011000110011100… |
… | …011011111100100011110111 |
3 | 112221200111021100100210110021 |
4 | 121323012130123330203313 |
5 | 104420440131022201314 |
6 | 1042252344530110011 |
7 | 33005063546165011 |
oct | 3173063433744367 |
9 | 487614240323407 |
10 | 114012531443959 |
11 | 33367496777115 |
12 | 1095448611b307 |
13 | 4b80449375a95 |
14 | 20223436bb1b1 |
15 | d2aada918324 |
hex | 67b19c6fc8f7 |
114012531443959 has 2 divisors, whose sum is σ = 114012531443960. Its totient is φ = 114012531443958.
The previous prime is 114012531443893. The next prime is 114012531443969. The reversal of 114012531443959 is 959344135210411.
It is a strong prime.
It is an emirp because it is prime and its reverse (959344135210411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114012531443959 - 27 = 114012531443831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114012531443969) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006265721979 + 57006265721980.
It is an arithmetic number, because the mean of its divisors is an integer number (57006265721980).
Almost surely, 2114012531443959 is an apocalyptic number.
114012531443959 is a deficient number, since it is larger than the sum of its proper divisors (1).
114012531443959 is an equidigital number, since it uses as much as digits as its factorization.
114012531443959 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 52.
The spelling of 114012531443959 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-one million, four hundred forty-three thousand, nine hundred fifty-nine".
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