114012533541073 has 2 divisors, whose sum is σ = 114012533541074. Its totient is φ = 114012533541072.

The previous prime is 114012533541001. The next prime is 114012533541113. The reversal of 114012533541073 is 370145335210411.

It is an a-pointer prime, because the next prime (114012533541113) can be obtained adding 114012533541073 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107292659419089 + 6719874121984 = 10358217^2 + 2592272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114012533541073 is a prime.

It is not a weakly prime, because it can be changed into another prime (114012533041073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006266770536 + 57006266770537.

It is an arithmetic number, because the mean of its divisors is an integer number (57006266770537).

Almost surely, 2^{114012533541073} is an apocalyptic number.

It is an amenable number.

114012533541073 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012533541073 is an equidigital number, since it uses as much as digits as its factorization.

114012533541073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

Adding to 114012533541073 its reverse (370145335210411), we get a palindrome (484157868751484).

The spelling of 114012533541073 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-three million, five hundred forty-one thousand, seventy-three".