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114012533541293 is a prime number
BaseRepresentation
bin11001111011000110011100…
…100011111100100110101101
3112221200111021111022100110022
4121323012130203330212231
5104420440132041310133
61042252345043051525
733005063603051462
oct3173063443744655
9487614244270408
10114012533541293
1133367497979952
1210954486970ba5
134b8044992b5ca
142022343aa5669
15d2aadabce998
hex67b19c8fc9ad

114012533541293 has 2 divisors, whose sum is σ = 114012533541294. Its totient is φ = 114012533541292.

The previous prime is 114012533541289. The next prime is 114012533541503. The reversal of 114012533541293 is 392145335210411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66520629616324 + 47491903924969 = 8156018^2 + 6891437^2 .

It is a cyclic number.

It is not a de Polignac number, because 114012533541293 - 22 = 114012533541289 is a prime.

It is a super-2 number, since 2×1140125335412932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114012533541793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006266770646 + 57006266770647.

It is an arithmetic number, because the mean of its divisors is an integer number (57006266770647).

Almost surely, 2114012533541293 is an apocalyptic number.

It is an amenable number.

114012533541293 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012533541293 is an equidigital number, since it uses as much as digits as its factorization.

114012533541293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 44.

The spelling of 114012533541293 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-three million, five hundred forty-one thousand, two hundred ninety-three".