1140125344133 has 4 divisors (see below), whose sum is σ = 1140141932160. Its totient is φ = 1140108756108.

The previous prime is 1140125344129. The next prime is 1140125344139. The reversal of 1140125344133 is 3314435210411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140125344133 - 2² = 1140125344129 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1140125344133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140125344139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8190485 + ... + 8328522.

It is an arithmetic number, because the mean of its divisors is an integer number (285035483040).

Almost surely, 2^{1140125344133} is an apocalyptic number.

It is an amenable number.

1140125344133 is a deficient number, since it is larger than the sum of its proper divisors (16588027).

1140125344133 is an equidigital number, since it uses as much as digits as its factorization.

1140125344133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16588026.

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 1140125344133 in words is "one trillion, one hundred forty billion, one hundred twenty-five million, three hundred forty-four thousand, one hundred thirty-three".