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114012535513127 is a prime number
BaseRepresentation
bin11001111011000110011100…
…101011011110000000100111
3112221200111021122000112022012
4121323012130223132000213
5104420440133042410002
61042252345153224435
733005063625603326
oct3173063453360047
9487614248015265
10114012535513127
1133367498aa6369
121095448756211b
134b8044a16bc84
14202234405a0bd
15d2aadae6dd52
hex67b19cade027

114012535513127 has 2 divisors, whose sum is σ = 114012535513128. Its totient is φ = 114012535513126.

The previous prime is 114012535513067. The next prime is 114012535513237. The reversal of 114012535513127 is 721315535210411.

It is a weak prime.

It is an emirp because it is prime and its reverse (721315535210411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114012535513127 - 220 = 114012534464551 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114012535513627) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006267756563 + 57006267756564.

It is an arithmetic number, because the mean of its divisors is an integer number (57006267756564).

Almost surely, 2114012535513127 is an apocalyptic number.

114012535513127 is a deficient number, since it is larger than the sum of its proper divisors (1).

114012535513127 is an equidigital number, since it uses as much as digits as its factorization.

114012535513127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126000, while the sum is 41.

The spelling of 114012535513127 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-five million, five hundred thirteen thousand, one hundred twenty-seven".