114012542003553 has 6 divisors (see below), whose sum is σ = 164684782894034. Its totient is φ = 76008361335696.

The previous prime is 114012542003533. The next prime is 114012542003567. The reversal of 114012542003553 is 355300245210411.

114012542003553 is a `hidden beast` number, since 1 + 1 + 40 + 1 + 25 + 42 + 0 + 0 + 3 + 553 = 666.

It can be written as a sum of positive squares in only one way, i.e., 94500329592384 + 19512212411169 = 9721128^2 + 4417263^2 .

It is not a de Polignac number, because 114012542003553 - 2³³ = 114003952068961 is a prime.

It is a super-2 number, since 2×114012542003553² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114012542003533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6334030111300 + ... + 6334030111317.

Almost surely, 2^{114012542003553} is an apocalyptic number.

It is an amenable number.

114012542003553 is a deficient number, since it is larger than the sum of its proper divisors (50672240890481).

114012542003553 is a wasteful number, since it uses less digits than its factorization.

114012542003553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12668060222623 (or 12668060222620 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 114012542003553 its reverse (355300245210411), we get a palindrome (469312787213964).

The spelling of 114012542003553 in words is "one hundred fourteen trillion, twelve billion, five hundred forty-two million, three thousand, five hundred fifty-three".