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1140129131 is a prime number
BaseRepresentation
bin100001111110100…
…1111110101101011
32221110100120010212
41003331033311223
54313333113011
6305044531335
740152636431
oct10375176553
92843316125
101140129131
11535633989
122799b0b4b
1315229122b
14ab5c6d51
156a16108b
hex43f4fd6b

1140129131 has 2 divisors, whose sum is σ = 1140129132. Its totient is φ = 1140129130.

The previous prime is 1140129103. The next prime is 1140129161. The reversal of 1140129131 is 1319210411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1140129131 - 210 = 1140128107 is a prime.

It is a super-2 number, since 2×11401291312 = 2599788870709630322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140129097 and 1140129106.

It is not a weakly prime, because it can be changed into another prime (1140129161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570064565 + 570064566.

It is an arithmetic number, because the mean of its divisors is an integer number (570064566).

Almost surely, 21140129131 is an apocalyptic number.

1140129131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140129131 is an equidigital number, since it uses as much as digits as its factorization.

1140129131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The square root of 1140129131 is about 33765.7982431928. The cubic root of 1140129131 is about 1044.6833685831.

Adding to 1140129131 its reverse (1319210411), we get a palindrome (2459339542).

The spelling of 1140129131 in words is "one billion, one hundred forty million, one hundred twenty-nine thousand, one hundred thirty-one".