11401300113 has 32 divisors (see below), whose sum is σ = 18357504000. Its totient is φ = 6148607616.

The previous prime is 11401300109. The next prime is 11401300147. The reversal of 11401300113 is 31100310411.

It is not a de Polignac number, because 11401300113 - 2² = 11401300109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11401300092 and 11401300101.

It is not an unprimeable number, because it can be changed into a prime (11401300013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50613 + ... + 159261.

It is an arithmetic number, because the mean of its divisors is an integer number (573672000).

Almost surely, 2^11401300113 is an apocalyptic number.

It is an amenable number.

11401300113 is a deficient number, since it is larger than the sum of its proper divisors (6956203887).

11401300113 is a wasteful number, since it uses less digits than its factorization.

11401300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108941.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11401300113 its reverse (31100310411), we get a palindrome (42501610524).

The spelling of 11401300113 in words is "eleven billion, four hundred one million, three hundred thousand, one hundred thirteen".