Base | Representation |
---|---|
bin | 10101001111001001… |
… | …00000100010110011 |
3 | 1002102120120001112211 |
4 | 22213210200202303 |
5 | 141322213101042 |
6 | 5123201232551 |
7 | 552351311056 |
oct | 124744404263 |
9 | 32376501484 |
10 | 11401300147 |
11 | 4920811606 |
12 | 2262332757 |
13 | 10c9102963 |
14 | 7a22d2a9d |
15 | 46ae0d017 |
hex | 2a79208b3 |
11401300147 has 2 divisors, whose sum is σ = 11401300148. Its totient is φ = 11401300146.
The previous prime is 11401300109. The next prime is 11401300283. The reversal of 11401300147 is 74100310411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11401300147 is a prime.
It is not a weakly prime, because it can be changed into another prime (11401300847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700650073 + 5700650074.
It is an arithmetic number, because the mean of its divisors is an integer number (5700650074).
Almost surely, 211401300147 is an apocalyptic number.
11401300147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401300147 is an equidigital number, since it uses as much as digits as its factorization.
11401300147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 11401300147 its reverse (74100310411), we get a palindrome (85501610558).
The spelling of 11401300147 in words is "eleven billion, four hundred one million, three hundred thousand, one hundred forty-seven".
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