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1140132017 is a prime number
BaseRepresentation
bin100001111110101…
…0000100010110001
32221110100201002202
41003331100202301
54313333211032
6305044552545
740152651023
oct10375204261
92843321082
101140132017
11535636072
122799b2755
1315229263b
14ab5c8013
156a161d62
hex43f508b1

1140132017 has 2 divisors, whose sum is σ = 1140132018. Its totient is φ = 1140132016.

The previous prime is 1140131999. The next prime is 1140132041. The reversal of 1140132017 is 7102310411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 643332496 + 496799521 = 25364^2 + 22289^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140132017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1140132017.

It is not a weakly prime, because it can be changed into another prime (1140132067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570066008 + 570066009.

It is an arithmetic number, because the mean of its divisors is an integer number (570066009).

Almost surely, 21140132017 is an apocalyptic number.

It is an amenable number.

1140132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140132017 is an equidigital number, since it uses as much as digits as its factorization.

1140132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 1140132017 is about 33765.8409787169. The cubic root of 1140132017 is about 1044.6842500487.

Adding to 1140132017 its reverse (7102310411), we get a palindrome (8242442428).

The spelling of 1140132017 in words is "one billion, one hundred forty million, one hundred thirty-two thousand, seventeen".