114013432019 has 2 divisors, whose sum is σ = 114013432020. Its totient is φ = 114013432018.

The previous prime is 114013431989. The next prime is 114013432037. The reversal of 114013432019 is 910234310411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114013432019 - 2¹² = 114013427923 is a prime.

It is a super-2 number, since 2×114013432019² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114013431982 and 114013432000.

It is not a weakly prime, because it can be changed into another prime (114013462019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006716009 + 57006716010.

It is an arithmetic number, because the mean of its divisors is an integer number (57006716010).

Almost surely, 2^114013432019 is an apocalyptic number.

114013432019 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013432019 is an equidigital number, since it uses as much as digits as its factorization.

114013432019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 114013432019 in words is "one hundred fourteen billion, thirteen million, four hundred thirty-two thousand, nineteen".