Base | Representation |
---|---|
bin | 1101100101110… |
… | …11010100001011 |
3 | 21221112111001102 |
4 | 12302323110023 |
5 | 213141412301 |
6 | 15151412015 |
7 | 2553045506 |
oct | 662732413 |
9 | 257474042 |
10 | 114013451 |
11 | 593a2aa2 |
12 | 3222400b |
13 | 1a80c0a6 |
14 | 111dc13d |
15 | a021b6b |
hex | 6cbb50b |
114013451 has 2 divisors, whose sum is σ = 114013452. Its totient is φ = 114013450.
The previous prime is 114013423. The next prime is 114013457. The reversal of 114013451 is 154310411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114013451 - 26 = 114013387 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (114013457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006725 + 57006726.
It is an arithmetic number, because the mean of its divisors is an integer number (57006726).
Almost surely, 2114013451 is an apocalyptic number.
114013451 is a deficient number, since it is larger than the sum of its proper divisors (1).
114013451 is an equidigital number, since it uses as much as digits as its factorization.
114013451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 114013451 is about 10677.7081342393. The cubic root of 114013451 is about 484.8998283927.
Adding to 114013451 its reverse (154310411), we get a palindrome (268323862).
The spelling of 114013451 in words is "one hundred fourteen million, thirteen thousand, four hundred fifty-one".
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